Soddalashtiring: x+6√x+8√x+4-x+6√x-2+6√x-2+4, bunda x≥2.

$x+6\sqrt{x}+8=(\sqrt{x}+2)(\sqrt{x}+4)$, shuning uchun birinchi kasr $\sqrt{x}+2$ ga teng. $x+6\sqrt{x-2}+6=(x-2)+6\sqrt{x-2}+8=(\sqrt{x-2}+2)(\sqrt{x-2}+4)$, shuning uchun ikkinchi kasr $\sqrt{x-2}+2$ ga teng. Ayirma: $(\sqrt{x}+2)-(\sqrt{x-2}+2)=\sqrt{x}-\sqrt{x-2}$.

Manba: UZBMB namunaviy test topshiriqlari (2022, mutaxassislik)