Agar n=-3, m=-2 va k=3 boʻlsa, (4n^2/m)^2/m^2n^2:k^3/(mn)^3^2/n^3 ning qiymatini toping.

$\frac{4n^2}{m}=\frac{36}{-2}=-18$, $\frac{k}{m^2n^2}=\frac{3}{36}=\frac{1}{12}$, $\frac{k^3}{(mn)^3}=\frac{27}{216}=\frac18$, $\frac{mk^2}{n^3}=\frac{-18}{-27}=\frac23$. Amallarni chapdan o‘ngga bajaramiz: $324\cdot\frac{1}{12}:\frac18\cdot\frac23=27\cdot8\cdot\frac23=144$. Ifoda amallar chapdan o‘ngga bajariladi deb o‘qilgan. Bo‘luvchini $\frac{k^3}{(mn)^3}\cdot\frac{mk^2}{n^3}$ ko‘paytma deb olinsa, 324 chiqadi, u esa variantlarda yo‘q.

Manba: UZBMB namunaviy test topshiriqlari (Milliy sertifikat, Matematika)