3-savol · UZBMB namunasi 3 / 9 x = 4 x=4 x = 4 bo‘lsa, x 2 − 4 4 x 2 ⋅ 2 x x + 2 \frac{x^2-4}{4x^2}\cdot\frac{2x}{x+2} 4 x 2 x 2 − 4 ⋅ x + 2 2 x ifodaning qiymatini toping.
A 0,25 B 0,05 C 0,02 D 0,01 Toʻgʻri javob: A) 0,25
Izoh: x 2 − 4 4 x 2 ⋅ 2 x x + 2 \frac{x^2-4}{4x^2}\cdot\frac{2x}{x+2} 4 x 2 x 2 − 4 ⋅ x + 2 2 x ifodani soddalashtirib olamiz:
x 2 − 4 4 x 2 ⋅ 2 x x + 2 = ( x − 2 ) ( x + 2 ) 4 x 2 ⋅ 2 x x + 2 = x − 2 2 x \frac{x^2-4}{4x^2}\cdot\frac{2x}{x+2}=\frac{(x-2)(x+2)}{4x^2}\cdot\frac{2x}{x+2}=\frac{x-2}{2x} 4 x 2 x 2 − 4 ⋅ x + 2 2 x = 4 x 2 ( x − 2 ) ( x + 2 ) ⋅ x + 2 2 x = 2 x x − 2
x − 2 2 x \frac{x-2}{2x} 2 x x − 2 ifodaga x = 4 x=4 x = 4 ni qo‘yib natijani hisoblaymiz, ya’ni:
x − 2 2 x = 4 − 2 2 ⋅ 4 = 2 8 = 1 4 = 0,25 \frac{x-2}{2x}=\frac{4-2}{2\cdot 4}=\frac{2}{8}=\frac{1}{4}=0{,}25 2 x x − 2 = 2 ⋅ 4 4 − 2 = 8 2 = 4 1 = 0 , 25 .
Manba: UZBMB namunaviy test topshiriqlari (2021, mutaxassislik). Sh.A.Alimov, O.R.Xolmuhamedov, M.A.Mirzaahmedov. Algebra, umumiy o‘rta ta’lim maktablarining 8-sinfi uchun darslik. “O‘qituvchi” nashriyot-matbaa ijodiy uyi. Toshkent−2019
Mavzudagi barcha savollar: Algebraik ifodalar, ifodalarni almashtirish Matematika: barcha mavzular