(3x^2-2)√2x-1-x√2x-1=0 tenglamaning ildizlari yigʻindisini toping.

Aniqlanish sohasi: $x\ge\frac{1}{2}$. $\sqrt{2x-1}\,(3x^2-x-2)=0$. $\sqrt{2x-1}=0$ dan $x=\frac{1}{2}$; $3x^2-x-2=0$ dan $x=1$ yoki $x=-\frac{2}{3}$ (sohaga kirmaydi). Ildizlar $\frac{1}{2}$ va 1, yig‘indisi $1{,}5$.

Manba: UZBMB namunaviy test topshiriqlari (2022, mutaxassislik)