2^4x+3-2^4x-7^4x-1-7^4x-2=0 tenglamaning haqiqiy ildizi x_0 boʻlsa, 4· x_0 ni toping.

$2^{4x}(8-1)=7^{4x}\left(\frac{1}{7}+\frac{1}{49}\right)$, ya’ni $7\cdot2^{4x}=\frac{8}{49}\cdot7^{4x}$. Bundan $\left(\frac{2}{7}\right)^{4x}=\frac{8}{343}=\left(\frac{2}{7}\right)^3$, demak $4x_0=3$.

Manba: UZBMB namunaviy test topshiriqlari (2022, mutaxassislik)