Ifodaning qiymatini toping: a^2-4a+11, bunda a=2+√5

$a^2-4a+11=(a-2)^2+7$. $a-2=\sqrt{5}$ bo‘lgani uchun $(\sqrt{5})^2+7=5+7=12$.

Manba: UZBMB namunaviy test topshiriqlari (2022, mutaxassislik)