Hisoblang: 7,2(1)-4,4(2)+31/90

$7{,}2(1)=\frac{721-72}{90}=\frac{649}{90}$, $4{,}4(2)=\frac{442-44}{90}=\frac{398}{90}$. U holda $\frac{649-398+31}{90}=\frac{282}{90}=3{,}1(3)$.

Manba: UZBMB namunaviy test topshiriqlari (Milliy sertifikat, Matematika)