Quyida keltirilgan sxemada X element birikmalarining oʻzgarishlari berilgan. D modda ohaktosh ekanligi…

$D$ — $CaCO_3$, demak $X$ — kalsiy. $Ca + 2H_2O \to Ca(OH)_2 + H_2\uparrow$ ($B$) $Ca(OH)_2 + 2HCl \to CaCl_2 + 2H_2O$ ($C$) — almashinish $CaCl_2 + K_2CO_3 \to CaCO_3\downarrow + 2KCl$ ($D$) — almashinish $CaCO_3 + H_2O + CO_2 \to Ca(HCO_3)_2$ ($E$) — birikish $Ca(HCO_3)_2 \xrightarrow{100^\circ} CaCO_3 + H_2O + CO_2$ — parchalanish $CaCO_3 \xrightarrow{1000^\circ} CaO + CO_2$ ($A$) — parchalanish $CaO + H_2O \to Ca(OH)_2$ — birikish Birikish reaksiyalari: $D + H_2O + CO_2$ va $A + H_2O$.

Manba: UZBMB namunaviy test topshiriqlari (2022, mutaxassislik)