1-savol · UZBMB namunasi 1 / 7 A va B aminokislota ekanligini bilgan holda, B moddani aniqlang.
Reaksiya Hosil bo‘lgan dipeptidning nisbiy molekular massasi 2 A → dipeptid + H 2 O 2A \to \text{dipeptid} + H_2O 2 A → dipeptid + H 2 O 274 A + B → dipeptid + H 2 O A + B \to \text{dipeptid} + H_2O A + B → dipeptid + H 2 O 249
A sistein B lizin C serin D glutamin kislota Toʻgʻri javob: A) sistein
Izoh: M r ( 2 A ) = 274 + 18 = 292 Mr_{(2A)} = 274 + 18 = 292 M r ( 2 A ) = 274 + 18 = 292 M r ( A ) = 292 / 2 = 146 Mr_{(A)} = 292/2 = 146 M r ( A ) = 292/2 = 146 M r ( A + B ) = 249 + 18 = 267 Mr_{(A+B)} = 249 + 18 = 267 M r ( A + B ) = 249 + 18 = 267 M r ( B ) = 267 − 146 = 121 Mr_{(B)} = 267 - 146 = 121 M r ( B ) = 267 − 146 = 121 H S − C H 2 − C H ( N H 2 ) − C O O H HS-CH_2-CH(NH_2)-COOH H S − C H 2 − C H ( N H 2 ) − C O O H
Manba: UZBMB namunaviy test topshiriqlari va ularni yechish bo‘yicha tavsiyalar (2020). A.Mutalibov va boshqalar. Organik kimyo. 10-sinf o‘quvchilari uchun darslik. G‘ofur G‘ulom nomidagi nashriyot-matbaa ijodiy uyi. Toshkent – 2017
Mavzudagi barcha savollar: Azotli organik birikmalar. Yuqori molekulyar birikmalar Kimyo: barcha mavzular