Grafikda berilgan maʻlumotlardan foydalanib p_C-p_A ayirmani (kPa) hisoblang. p_C va p_A lar mos ravishda…

Bitta qo‘shimcha chiziq tortish orqali quyidagilarni yozish mumkin. $\frac{V_B-V_A}{T_B-T_A}=\frac{V_C-V_A}{T_C-T_A}=\mathrm{tg}A$ $\frac{0{,}1}{300}=\frac{V_C-0{,}3}{900}\Rightarrow V_C=\frac{900\cdot 0{,}1}{300}+0{,}3=0{,}6$ Ideal gaz holat tenglamasidan foydalansak $\frac{p_AV_A}{T_A}=\frac{p_CV_C}{T_C}\Rightarrow p_C=\frac{T_C}{T_A}\cdot\frac{p_AV_A}{V_C}\Rightarrow p_C=\frac{1200\cdot 120\cdot 10^3\cdot 0{,}3}{300\cdot 0{,}6}=240$ kPa Oxirgi qadam $p_C-p_A=(240-120)$ kPa $=120$ kPa

Manba: UZBMB namunaviy test topshiriqlari va ularni yechish bo‘yicha tavsiyalar (2020). Fizika 9-sinf, P.Q. Habibullayev va b., G‘afur G‘ulom nomidagi nashriyot-matbaa ijodiy uyi, Toshkent – 2019