Teng massali A va B jismlar qiya tekislikdan qanday tezlanish (m/s^2) bilan tushadi? Bunda _A=0; _B=0,5…

Yolg‘iz qolganda $A$ ning tezlanishi $g\sin\alpha=6$ m/s$^2$, $B$ niki $g(\sin\alpha-\mu_B\cos\alpha)=10(0{,}6-0{,}5\cdot 0{,}8)=2$ m/s$^2$; demak $A$ $B$ ni itaradi va ular birga harakatlanadi. $2ma=2mg\sin\alpha-\mu_B mg\cos\alpha$, bundan $a=g\sin\alpha-\frac{\mu_B g\cos\alpha}{2}=6-2=4$ m/s$^2$.

Manba: UZBMB namunaviy test topshiriqlari (2022, mutaxassislik)